WebGiven,a=−6d=− 211−(−6)= 21Formula,S n= 2n[2a+(n−1)d]−25= 2n[2(−6)+(n−1) 21]−50=n[ 2−24+n−1]n 2−25n+100=0(n−20)(n−5)=0∴n=5,20Therefore the number of terms … Web14 apr. 2024 · The team fired Hextall, Burke and assistant general manager Chris Pryor on Friday after the Penguins failed to reach the playoffs for the first time in 17 years. The …
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Web19 dec. 2024 · ⇒ a + d = 2 and a + 6d = 22 Solving these two equations, we get a = – 2 and d = 4. S n = [2a + (n – 1) d] ∴ S 30 = [2 × (–2) + (30 – 1) × 4] ⇒ 15 (–4 + 116) = 15 × 112 = 1680 Hence, the sum of first 30 terms is 1680. Example 6: Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by 3. Solution. Web14 jan. 2024 · answered Jan 14, 2024 by vikash (13.6k points) selected Dec 16, 2024 by Vikash Kumar Best answer Solution: Given AP is -6, -11/2, -5… Here a = –6, d = (–11/2) …
WebAnswer (1 of 3): First term a =-6 Commondifference d =0.5 Number of terms =n Sum =n/2 (2a +(n-1)d) = -25 n/2(-12+(n-1)0.5) = -25 n/2(-12 +0.5n -0.5) = -25 n/2(-12.5 ... WebHow many terms of the AP 27, 24, 21, … should be taken so that their sum is 0 Q. How many terms of the AP 9, 17, 25, ... must be taken so that their sum is 636?
WebAP will be –15, –13, –11, –9, –7 So, resulting sum will be –55 because all terms are negative. When n = 11, AP will be –15, –13, –11, –9, –7, –5, –3, –1, 1, 3, 5 So resulting sum will be –55 because the sum of terms 6 th to 11 th is zero. Concept: Sum of First n Terms of an A.P. Is there an error in this question or solution? WebThe AP is -6, -11/2, -5, … It is an AP with the first term as -6 and the common ratio is 1/2. Sn = -25 = (n/2) [2a + (n-1)d] = (n/2) [-12 + (n-1)* (1/2)] = (n/2) [-12–1/2 + (n/2)] = (n/2) [-25/2 + (n/2)] -25*4 = n [-25+n] n^2–25n+100 = 0 (n-20) (n-5) = 0 n = 20 or 5. So either 5 terms or 20 terms of the AP will add up to -25. Answer. 2.1K views
Web9 dec. 2024 · Answer: No of terms = 5 ,20 Step-by-step explanation: Given : AP : -6, -11/2 , -5 To find: No of terms to give sum = -25 Steps: Firstly e calculate the common …
WebAn AP consists of 50 terms of which 3 rd term is 12 and the last term is 106. Find the 29 th term. Medium View solution > View more More From Chapter Arithmetic Progressions … iqbal tomb informationWeb18 aug. 2024 · The AP: -6, -11/2, -5, -9/2,…… To find We need to find how many terms of a series are zero. Solution The common difference between terms d is -11/2- (-6) =1/2. … iqbal tomb weatherWebGiven AP is : 1, 6, 11, 16…… First term, a = 1 ; Common difference = 5 Sum of n terms of AP, Sn = (n/2) [2a+ (n-1)d] Let there be n terms in the AP such that Sn= 148 148= (n/2) [2 (1)+ (n-1) (5)] 148 = (n/2) [2+5n-5] 148 = (n/2) [5n-3] 5n²-3n-296=0 This equation has one +ve root, n= 8 8 terms of AP are , 1, 6, 11, 16, 21, 26, 31, 36 Ans: 8 terms 1 iqbal watch oWebHow many terms of the A.P. 27, 24, 21, …, should be taken so that their sum is zero? CISCE ICSE Class 10. Question Papers 359. Textbook ... NCERT Solutions for Class 11 Maths; NCERT Solutions for Class 11 Physics; NCERT Solutions for Class 11 Chemistry; NCERT Solutions for Class 11 Biology; orchid hotel angeles city philippinesWebTherefore, the sum of the first 5 terms or the sum of the first 11 terms of an AP is equal to -55. The 11 terms of the series are -15, -13, -11, -9, -7, -5, -3, -1, 1, 3, 5. The reason for … iqbal twomblyWeb20 nov. 2013 · CBSE Most Important Questions for Class 11 commerce; CBSE Most Important Questions for Class 12 science; CBSE Most Important Questions for Class 12 commerce; ... how many terms of an AP 1,4,7...must be taken to give a sum of 51? Asked by jaiprakashprasadr 17 Jul, 2024, 11:03: PM. ANSWERED BY EXPERT. orchid hotel buffet lunch priceWebS36 = 36 2[2×20+(36−1) −2 3] = 18[40−35× 2 3] = 18[40− 70 3] = 18×( 120−70 3) = 6×50 = 300. it satisfies for n = 36. So let's find the sum of terms from 26th to 36th term (the 11 … iqbal watch online