WebFeb 28, 2024 · Applies to: SQL Server SSIS Integration Runtime in Azure Data Factory. Returns an integer representing a datepart of a date. Syntax DATEPART(datepart, date) Arguments. datepart Is the parameter that specifies for which part of the date to return a new value. date Is an expression that returns a valid date or a string in date format. … WebJul 21, 2014 · I would suggest that you just write the case statement yourself using datename (): select (case datename (dw, aws.date) when 'Monday' then 1 when …
select - How to get data of current week Start on Saturday end …
WebDec 19, 2024 · You can combine current_date with day_of_week to get the last Sunday: presto:default> SELECT date_add ('DAY', -day_of_week (current_date), current_date); _col0 ------------ 2024-12-15 (1 row) Note: when it's run on Sunday, this returns previous Sunday. You can easily adjust this as needed with if. Tested on Presto 326. WebOct 7, 2024 · SQL Server, SQL Server Express, ... Select , DATENAME("dw", sales_day) as day_week1, DATEPART("dw", sales_day) as day_week2, count(*) as Number ... The idea is to know which days of week are with peak value, so I need to know the average of sales in each day of the all weeks of the year. tips to help your vision
SQL获取年月日时分秒的函数 - 河耶悦悦 - 博客园
WebNov 10, 2015 · Whenever there is a gap, -- there will be a new group groups AS ( SELECT ROW_NUMBER() OVER (ORDER BY date) AS rn, dateadd(day, -ROW_NUMBER() OVER (ORDER BY date), date) AS grp, date FROM dates ) SELECT COUNT(*) AS consecutiveDates, MIN(week) AS minDate, MAX(week) AS maxDate FROM groups … WebApr 4, 2012 · It will make your weeks start on Monday or Tuesday or Wed... etc. dependant on what day of the week you have set as @pDate. Create parameters DECLARE @pDate Date = NULL --Replace with your date, which will also be the first day of the week DECLARE @pDatePart SMALLINT = DATEPART (dw, @pDate) Then put this case … WebOct 1, 2024 · DECLARE Start_day date:=to_date ('30-03-2012','DD-MM-YYYY'); check_date DATE:=SYSDATE; Day_of_week NUMBER; i NUMBER; BEGIN i:=to_char (Start_day,'D'); day_of_week:=mod ( (to_char (check_date,'D') - (i-1)+7),7); if day_of_week=0 THEN day_of_week:=7; end if; dbms_output.put_line (day_of_week); … tips to help you lose belly fat